Interview Question for Software Engineer at Amazon.com:

Here's an easy to understand version in python. Instead of chr(48 + nNum) you could just do str(nNum) but it can't hurt to demonstrate familiarity with ASCII.

def to_string(number):
    chars = []
    while number > 0:
        nNum = number % 10
        number /= 10
        chars.append(chr(48 + nNum))
    chars.reverse()
    return chars

Which would give something like
>>> to_string(34839)
['3', '4', '8', '3', '9']