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Newfield Wireless Software Engineer Interview Question

I interviewed in Berkeley, CA and was asked:
"Count the number of even-digit numbers below 10^9 that are divisible by 7 and 13."
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Part of a Software Engineer Interview Review - one of 17 Newfield Wireless Interview Reviews

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First, The number which is divisible by 7 and 13 will be multiple of (7*13=91) 91.
so X=10^9-(10^9 % 91) will give the largest number lessthan 10^9 which is divisible by both 7 and 13.
X/91=10989010 will give the number of digit which is divisible by 7 and 13.
since we need only even number lets divide it by two (10989010 / 2= 5494505)

so it has 5494505 even-digit below 10^9 that are divisible by 7 and 13.

- Prakash Perumal on Apr 11, 2014

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