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I interviewed in Penn State University, PA and was asked:
"Main question was verifying whether a binary tree was a BST, given the function header that looked like public boolean isBST(root). He stated no other functions could be created and that child nodes did not have links to their parents."
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Answers & Comments

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He was looking for me to use a helper function to pass the parent's value in.

boolean isBST(Node root) {
   return isBSTHelper(root.left, root.value, isLeft) && isBSTHelper(root.right, root.value, isRight);

something similar to this. Since he told me I could not use extra functions I could not come up with an answer which is why I am bitter / negative about this interview.
- Interview Candidate on Apr 2, 2014
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Basically, what you would have in isBST is the stop condition (i.e. if left < current-node < right), then recursively whether isBST(left) && isBST(right) is true.
- Khoa on Apr 5, 2014

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