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Interview Question for Financial Analyst at American Airlines:
Nov 4, 2009
What is the probability of throwing 11 and over with 2 dices
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0 of 7 people found this helpful
Dec 7, 2009
If you are rolling two dice the chances of getting an 11 and OVER is 2/12= 1/6.
You can roll a 6 and a 5 to equal 11 and you can roll a 6 and a 6 and get 12 which is OVER 11, therefore the answer should be 1/6.
You can roll a 6 and a 5 to equal 11 and you can roll a 6 and a 6 and get 12 which is OVER 11, therefore the answer should be 1/6.
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5 of 5 people found this helpful
Jan 11, 2010
The answer is 1/12 because there are two ways of rolling 11, rolling a 5 and a 6 or rolling a 6 and a 5 (for probability purposes there are indeed two different results). There is only 1 way to roll over 11 (two 6's). That means that out of 36 possible combinations, 3 qualify as being equal to or greater than 11, which means that the probability is 3/36, which reduces to 1/12.
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0 of 1 people found this helpful
Jan 18, 2010
All possible results when throwing 2 dices ( 2-3 combination IS THE SAME as 3-2, you know it if you ever played dice, I don't know what are the probability purposes Casey is talking about ):
(1,1)
(1,2) (2,2)
(1,3) (2,3) (3,3)
(1,4) (2,4) (3,4) (4,4)
(1,5) (2,5) (3,5) (4,5) (5,5)
(1,6) (2,6) (3,6) (4,6) (5,6) (6,6)
so there are 21 combinations, only (5,6) and (6,6) are >=11,
so the answer is: 2/21=9.52%
(1,1)
(1,2) (2,2)
(1,3) (2,3) (3,3)
(1,4) (2,4) (3,4) (4,4)
(1,5) (2,5) (3,5) (4,5) (5,5)
(1,6) (2,6) (3,6) (4,6) (5,6) (6,6)
so there are 21 combinations, only (5,6) and (6,6) are >=11,
so the answer is: 2/21=9.52%
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Jan 18, 2010
Casey's right, 3/36. Peter, it isn't an ordered problem but there are two rolls out of the 36 possible that can be 11 (6 on die a, 5 on die b, and vice versa). Add that to the one way you can roll boxcars (6 on die a, 6 on b), totally of 3 winning instances out of 36 possible.
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Jan 18, 2010
OK, you are right Casey...I made myself believe that what matters is the final sum, so unless they come up with dice that have 12 sides...I'm wrong :)
Thanks Grant
Thanks Grant
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0 of 2 people found this helpful
Jan 18, 2010
I think the question is oriented to find out if you are actually listening. You can not throw 11 AND over. You can throw 11 OR over. So, the answer is 0. Impossible.
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Jan 18, 2010
"Dices"? Did you just say "dices"? Excuse me for answering your question with a question, but what was the highest grade of grammar school education you recall passing? If I got this job, is there any possibility, that is, any chance higher than zero, that you would be my boss? How did you get to your current position in this organization? Can I go now?
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Jan 19, 2010
I'm with Jeff and Carlos- "dice" is the plural of "die". Geez. However, if the question actually is "what is the probability of getting 11 or greater on a single throw with a pair of dice," then the answer is 50%. It either will or will not be 11 or greater.
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Jan 19, 2010
1) Same as Jeff - "dices" makes no sense
2) How many sides are there on each die? Don't assume that all dice have six sides.
2) How many sides are there on each die? Don't assume that all dice have six sides.
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