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Bloomberg L.P. Financial Software Developer Interview Question

I interviewed in New York, NY and was asked:
"Write a java program that can convert a string of numbers (e.g. "5387") into an integer (5387)."
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Part of a Financial Software Developer Interview Review - one of 1,728 Bloomberg L.P. Interview Reviews

Answers & Comments

of 0
You can do math on individual characters, so subtract a constant from '5' and you can transform that character into an actual integer, 5. Then you need the String class and the Math.Pow() function. Don't forget to import the library that contains Math.Pow() !
- Interview Candidate on Feb 8, 2012
of 1
why do you need Math.pow()?
will this work?
fun() // input 5467
// take first character and transform into integer
//multiply by 10 * index of character which is zero
that is 5 + 0 = 5
then take the next character and transform into integer
now multiply 5 * 10 * index of character which is one
50 +4 = 54
540+ 6 = 546
5460 + 7 = 5467
running time is O(k) k = no of digits
or O(n) n being the number
- nmc on Feb 17, 2012
of 0
The way I did it was (for your example of 5467) essentially 5000 + 400 + 60 + 7. It's the first solution that came to mind and since that hour long portion of the interview seemed to be winding down, I just went with it. Not a pretty solution, but it does get the right answer.

For your solution, I understand what you're doing but I think your description of it is a bit off, or at least confusing. The you don't multiply by the index of the character at any time. What you're doing is just multiplying the sum to that point by 10 before adding the next character... i.e. in pseudo code,

sum = 0;
n = (length of the string of characters);
for(i==0; i < n; i++) {
sum *= 10;
sum+= (converted integer value of the character at index i);

So the first time through the loop when the index is zero, the initial sum multiplied by 10 is still zero, so you add 5 and get the running sum to be 5. Iteration 2, 5*10 = 50, add the next integer and you get 54, and so on. And that is a far more elegant solution, definitely. Thanks for pointing it out!
- Interview Candidate on Feb 19, 2012
of 0
If Java is allowed than why to do all these things. Why not directly use wrapper calss Integer and convert a string to integer.

String s="12345";
int i = Integer.parseInt(s);

Simple !
- Pratik on Apr 13, 2013

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