Intuit Interview Question
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Interview Question for Software Engineer at Intuit:
Oct 24, 2011
Helpful Question?
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Answers & Comments (2)
Dec 22, 2011
Perhaps a bit more efficient:
var palindrome = "dogeeseseegod"
int x = 0;
int y = palindrome .length-1;
while(x <= y)
{
if(palindrome [x] != palindrome [y])
return false;
x++;
y--;
}
return true;
var palindrome = "dogeeseseegod"
int x = 0;
int y = palindrome .length-1;
while(x <= y)
{
if(palindrome [x] != palindrome [y])
return false;
x++;
y--;
}
return true;
Helpful Answer?
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No
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