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Murex Integration Consultant Interview Question

I interviewed in New York, NY and was asked:
"square root algorithm"
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Answer

Part of a Integration Consultant Interview Review - one of 28 Murex Interview Reviews

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double squareRoot = number/2;
       do
        {
            g=squareRoot;
            squareRoot = (g + (number/g))/2;
            System.out.println(" g =" +g + " squareRoot =" +squareRoot);
        }
        while((g-squareRoot)!=0);

- Sahin on Feb 18, 2014

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