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www.palantir.com Palo Alto, CA 500 to 999 Employees
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Interview Question for Embedded Analyst at Palantir Technologies:
Mar 30, 2012

write a function that finds the remainder between two numbers using only addition, sutraction and multiplication.

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Answers & Comments (5)

0 of 7 people found this helpful

Apr 17, 2012

by Anonymous:

var x;
var y;
var solution;
var TestSol;
var Remainder;

x * (1/y) = solution;
solution*y = TestSol;
if (TestSol = x)
{
   document.write("Remainder is zero");
}
else
{
x - TestAns = Remainder;
document.write (Remainder);
}
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0 of 2 people found this helpful

Apr 17, 2012

by Anonymous:

Oops, forgot to include parseInt()
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Jul 2, 2012

by erez:

the first solution is wrong..(1/y) is division dude..

I think the solution is something like this. Suppose x, y are your numbers and you want to find remainder(y/x).

z = x
while z < y
i++
z = x*i
end

remainder = y - (z*(i-1))
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6 of 6 people found this helpful

Jul 5, 2012

by Jake S:

This is pretty easy, guys. You don't want to be doing extraneous multiplication because it is veryyyy slowwwww.

X and Y are the numbers to find the remainder of, assume X > Y.

while(x > y) {
x = x - y
}
return x

Example: 10, 4
10 > 4
x = 10 - 4 = 6

6 > 4
x = 6 - 4 = 2

2 < 4
return 2
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Oct 9, 2012

by Anonymous:

but if u do a binary search while multiplying then it will be faster then the subtraction method.
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Palantir Technologies – Why Work for Us?

Palantir Technologies builds software platforms that help human experts perform powerful, collaborative analysis of data at scale. Palantir’s software is deployed at public institutions, private enterprises, and in the… — Full Overview

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