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LinkedIn Interviews

Updated Mar 26, 2015
Updated Mar 26, 2015

Interview Experience

Interview Experience

54%
17%
28%

Getting an Interview

Getting an Interview

32%
31%
17%

Interview Difficulty

3.1
Average

Interview Difficulty

Hard

Average

Easy
  1. 8 people found this helpful  

    Software Engineer Interview

    Anonymous Employee
    Anonymous Employee
    Interview Details

    // Question 1

    /**
     * Returns a^b, as the standard mathematical exponentiation function
     */
    public double pow(double a, int b) {
        // implementation here
        if(b == 0){
           return a==0?Integer.MIN_VALUE:1;
        }
        if(b==1){
            return a;
        }
        if(a==1){
            return 1;
        }
        boolean isNegPower = false;
        if(b<0){
            isNegPower = true;
        }
        double result = powHelper(a,Math.abs(b));
        if(isNegative){
            return 1/result;
        }
        return result;
    }

    private double powHelper(double a, int b){
        if(b==1){
            return a;
        }
        if(b&1){
            return a*powHelper(a,b-1);
        }
        int result = powHelper(a,b/2)
        return result * result;
    }

    // Question 2

    /* This class will be given a list of words (such as might be tokenized
     * from a paragraph of text), and will provide a method that takes two
     * words and returns the shortest distance (in words) between those two
     * words in the provided text.
     * Example:
     * WordDistanceFinder finder = new WordDistanceFinder(Arrays.asList("the", "quick", "brown", "fox", "quick"));
     * assert(finder.distance("fox","the") == 3);
     * assert(finder.distance("quick", "fox") == 1);

     */
    public class WordDistanceFinder {

        Map<String,List<Integer>> wordToPos = new HashMap<>();
        public WordDistanceFinder (List<String> words) {
            // implementation here
            for(int pos=0;pos<words.size();++pos){
                String word = pos.get(pos);
                List<Integer> posList = wordToPos.get(word);
                if(posList==null){
                    posList = new ArrayList<Integer>();
                }
                posList.add(pos);
                wordToPos.put(word,posList);
            }
        }
        public int distance (String wordOne, String wordTwo) {
            return findMin(wordToPos.get(wordOne),wordToPos.get(wordTwo));
        }

        private int findMin(List<Integer> pos1, List<Integer> pos2){
            if(pos1==null||pos2==null){
                return -1;
            }
            int i=0,j=0;
            int min = Integer.MAX_VALUE;
            while(i<pos1.size()&&j<pos2.size()){
                int currentMin = Math.abs(pos1.get(i)-pos2.get(j))
                if(min>currentMin){
                    min = currentMin;
                }
                if(pos1.get(i)<pos2.get(j)){
                    ++i;
                }else{
                    ++j;
                }
            }
            return min;
        }
    }

    // Question 3

    public interface TwoSum {
        /**
         * Stores @param input in an internal data structure.
         */
        void store(int input);

        /**
         * Returns true if there is any pair of numbers in the internal data structure which
         * have sum @param val, and false otherwise.
         * For example, if the numbers 1, -2, 3, and 6 had been stored,
         * the method should return true for 4, -1, and 9, but false for 10, 5, and 0
         */
        boolean test(int val);
    }
    public class MyTwoSum implements TwoSum{
        private List<Integer> list = new ArrayList<>();

        void store(int input){
            list.add(input);
        }

        boolean test(int val){
            Set<Integer> elSeen = new HashSet<Integer>();
            for(int el:list){
                if(checkOverflow(val,el){
                    return false;
                }
                if(elSeen.contains(val-el)){
                    return true;
                }
                elSeen.add(el);
            }
            return false;
        }
    }
    bool checkOverflow(int val, int el){
        int result = val-el;
        if(val<0&&el>0){
            if(result>val){
                return true;
            }
        }
        if(val>0&&el<0){
            if(result<val){
                return true;
            }
        }
        return false;
    }

    Interview Questions
    • // Question 1

      /**
       * Returns a^b, as the standard mathematical exponentiation function
       */
      public double pow(double a, int b) {
          // implementation here
          if(b == 0){
             return a==0?Integer.MIN_VALUE:1;
          }
          if(b==1){
              return a;
          }
          if(a==1){
              return 1;
          }
          boolean isNegPower = false;
          if(b<0){
              isNegPower = true;
          }
          double result = powHelper(a,Math.abs(b));
          if(isNegative){
              return 1/result;
          }
          return result;
      }

      private double powHelper(double a, int b){
          if(b==1){
              return a;
          }
          if(b&1){
              return a*powHelper(a,b-1);
          }
          int result = powHelper(a,b/2)
          return result * result;
      }

      // Question 2

      /* This class will be given a list of words (such as might be tokenized
       * from a paragraph of text), and will provide a method that takes two
       * words and returns the shortest distance (in words) between those two
       * words in the provided text.
       * Example:
       * WordDistanceFinder finder = new WordDistanceFinder(Arrays.asList("the", "quick", "brown", "fox", "quick"));
       * assert(finder.distance("fox","the") == 3);
       * assert(finder.distance("quick", "fox") == 1);

       */
      public class WordDistanceFinder {

          Map<String,List<Integer>> wordToPos = new HashMap<>();
          public WordDistanceFinder (List<String> words) {
              // implementation here
              for(int pos=0;pos<words.size();++pos){
                  String word = pos.get(pos);
                  List<Integer> posList = wordToPos.get(word);
                  if(posList==null){
                      posList = new ArrayList<Integer>();
                  }
                  posList.add(pos);
                  wordToPos.put(word,posList);
              }
          }
          public int distance (String wordOne, String wordTwo) {
              return findMin(wordToPos.get(wordOne),wordToPos.get(wordTwo));
          }

          private int findMin(List<Integer> pos1, List<Integer> pos2){
              if(pos1==null||pos2==null){
                  return -1;
              }
              int i=0,j=0;
              int min = Integer.MAX_VALUE;
              while(i<pos1.size()&&j<pos2.size()){
                  int currentMin = Math.abs(pos1.get(i)-pos2.get(j))
                  if(min>currentMin){
                      min = currentMin;
                  }
                  if(pos1.get(i)<pos2.get(j)){
                      ++i;
                  }else{
                      ++j;
                  }
              }
              return min;
          }
      }

      // Question 3

      public interface TwoSum {
          /**
           * Stores @param input in an internal data structure.
           */
          void store(int input);

          /**
           * Returns true if there is any pair of numbers in the internal data structure which
           * have sum @param val, and false otherwise.
           * For example, if the numbers 1, -2, 3, and 6 had been stored,
           * the method should return true for 4, -1, and 9, but false for 10, 5, and 0
           */
          boolean test(int val);
      }
      public class MyTwoSum implements TwoSum{
          private List<Integer> list = new ArrayList<>();

          void store(int input){
              list.add(input);
          }

          boolean test(int val){
              Set<Integer> elSeen = new HashSet<Integer>();
              for(int el:list){
                  if(checkOverflow(val,el){
                      return false;
                  }
                  if(elSeen.contains(val-el)){
                      return true;
                  }
                  elSeen.add(el);
              }
              return false;
          }
      }
      bool checkOverflow(int val, int el){
          int result = val-el;
          if(val<0&&el>0){
              if(result>val){
                  return true;
              }
          }
          if(val>0&&el<0){
              if(result<val){
                  return true;
              }
          }
          return false;
      }
       
      Answer Question
    Declined Offer
    Neutral Experience
    Average Interview

LinkedIn Awards & Accolades

Something missing? Add an award
Employees' Choice -50 Best Places to work, Glassdoor, 2013
Glassdoor’s Employees’ Choice Award - Top 50 Large Companies, Glassdoor, 2014

Additional Info

Unlock Profile
Website www.linkedin.com
Headquarters Mountain View, CA
Size 5000+ Employees
Founded 2003
Type Company - Public (LNKD)
Industry Information Technology
Revenue $1 to $2 billion (USD) per year
Competitors XING AG, Monster Worldwide

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