Assistant Trader Intern Interview Questions | Glassdoor

# Assistant Trader Intern Interview Questions

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Assistant trader intern interview questions shared by candidates

## Top Interview Questions

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### Trader Assistant Intern at DRW was asked...

Mar 2, 2010
 What is the chance that at least two people were born on the same day of the week if there are 3 people in the room? 6 Answers ~89.8% incorrect. 1-364/365*363/365 = 1-.9918 = .0082...something like this for 2 people, for 2+ add in the chance of 3 of 3. So first guy then gets 365/365 choices, next two get 1/365 Also incorrect... They are asking if they were born the same day of the week not the exact same day as Chase alluded to. In this case the easiest way to do the problem is 1- probability that no one was born on the same day. 1-(1)(6/7)(5/7)+ 19/49 or 38.78% Show More Responses My bad =19/49 Or you can calculate it directly: The chance of SELECTED two people(but not three) that are born on the same day is 1* 1/7 - 1/7*1/7 =6/49 Now we have 3 chooses 2 = 3 possible pairs, so the probability that any PAIR(but not all three) that are born on the same day is 3* 6/49 = 18/49. However, since the question asks "at least 2", we will need to add the possibility that all three are born at the same day, which is 1/7 * 1/7 = 1/49. So the final result is 18/49 + 1/49 = 19/49 This obviously is a worse way of calculating it, but it's an alternative for some people who wants to think "straight". 1-(7/7*6/7*5/7) = 19/49 = 0.39 # 1 minus the opportunities that all 3 people were born in different day of the week.

### Assistant Trader Intern at Susquehanna International Group was asked...

Feb 18, 2011
 Five guys, all of different ages enter a bar and take a seat at a round table. What is the probability that they are seated in ascending order of age? (clockwise or counter-clockwise) 2 Answers 5! or 120 total seating positions. 5 possible starting positions because the table is round. 2 possible directions. This makes 10 arrangements that fulfill the prompt, ie P = 10/5! = 1/12 Make the youngest person a fixed point. The second youngest can sit on 2 seats in 4 remaining seats (left or right of the youngest). The third youngest can sit on 1 seat in the 3 remaining because we defined ordered by previous step. Fourth youngest can sit on 1/2. Last person 1/1 2/4*1/3*1/2=1/12

### Assistant Trader Intern at Gray Whale was asked...

Nov 14, 2012
 We are playing a card game where we each have a deck and flip one card each round, and the first person who gets an ace wins (kind of like war, but only an ace wins). If there is one standard 52 card deck, and one deck with 4 standard decks (208 cards total), which deck would you choose and why? 1 Answer I would pick the smaller deck, since after the first flip, the 4 decks has a probability of 16/207 and the smaller deck has a probability of 4/51, which is higher.

### Trader Assistant Intern at DRW was asked...

Mar 7, 2012
 You have 1 minute to solve as many mental math problems as you can. Proceeded to list of problems, each more difficult than last. 1 Answer Try http://www.arscalcula.com/

### Trader Assistant Intern at DRW was asked...

Feb 14, 2011
 Why trading?

### Assistant Trader Intern at Susquehanna International Group was asked...

Dec 7, 2012
 Make me a market on the population of Nigeria.
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