Brokerage Services interview questions | Glassdoor

# Brokerage Services interview questions

Northwestern Mutual Interviews

www.northwesternmutual.com /  HQ: Milwaukee, WI

2,039 Interviews

2.4 Easy

Merrill Lynch Interviews

www.ml.com /  HQ: New York, NY

659 Interviews

2.7 Average

Regions Financial Interviews

www.regions.com /  HQ: Birmingham, AL

326 Interviews

2.7 Average

## Interview Questions

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### Portfolio Manager at Regions Financial was asked...

Aug 4, 2013
 How would you handle a client who told you that you don't know what you are talking about because you have no experience?1 AnswerI said that the advice and counsel I was offering didn't originate with me but with best practices industry wide

Sep 27, 2015

### User Experience/UI Designer at FOLIOfn was asked...

Mar 5, 2016
 Can you describe what your design process is?2 AnswersTell me about a time when a senior executive or client disagreed with your design - how did you handle it?I first figure out what the needs of the customer are and determine how I can design the product to best fit those needs and make the product easy to use. I then focus on the aesthetic part of the project and make it look as good as possible.

Jun 10, 2010

### Summer Intern at Five Rings Capital was asked...

Apr 25, 2012
 • Is 1027 a prime number? • How would you write an algorithm that identifies prime numbers? • 2 blue and 2 red balls, in a box, no replacing. Guess the color of the ball, you receive a dollar if you are correct. What is the dollar amount you would pay to play this game? 6 AnswersAn algorithm for testing prime numbers is trial testing, test whether whether the number is dividable by an integer from 2 to its square root. For the color guessing game, the expected number of dollars you get is the average identity between a permutation of rrbb and rrbb, which is 2.For the prime number testing, only the number 2 and then odd numbers need to be tested. If it is not divisible by 2, there is no need to test against any other even number. So start with 2, then 3, then increment by 2 after that (3,7,9,...) until you are greater than the square root (then it's prime), or you find a divisible factor (it is not prime). To test for divisibility, we are looking for a remainder of zero - use a MOD function if available. Taking the integer portion of the quotient and subtracting from the actual quotient: if the difference is zero, then the remainder is zero and we have a divisible factor. If the difference is nonzero, then it is not divisible and continue testing. In this case, we find that dividing by 13 gives 79 with no remainder, so it is not prime.For the guessing game, the minimum winnings are \$2 every time with the proper strategy. I'm assuming the rules are you pay to play and you get to guess until there are no more marbles. Say you guess wrong the first attempt. (you guess blue and it was red). So now you know there are 2 blue, 1 red. Your logical choice is to choose blue again, since there are more of them. But say you guess wrong again. Now you know there are 2 blue left, so you will win on both of the last 2 draws. If you were correct on one or both of the first two trials, then you could wind up with an even chance on the third trial, so you would win that some of the time, then you'll always win on the last trial.Show More ResponsesDavid, I think we could pay more that \$2 and still come out on top. You logic seems sound, but looking at the probabilities I see: 1/2+1/3*(2)+2/3*(5/2) = 17/6 = ~2.83 Choosing the first ball, we obviously have an expected value of 1/2. Then, WLOG, we are left with RRB. Clearly we then choose R as this gives us a 2/3 shot at picking correctly. If it is R, then we get that \$1, have a 50% shot at the next, and are assured the last, giving us, on average, \$2.5. If it is B, then we know the next two will be R, giving us \$2. As you can see, with an optimal strategy, we should expect to make ~\$2.83 per round.Take the square root fo 1027. You get 32.04. Need only to check if divisible by prime numbers from 1 to 32, which include 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, and 31 For algorithm, see Lucas' test on Wikipedia, where there is also pseudocode.1027 = 1000 + 27 = 10^3 + 3^3 and you know you can factor a^3 + b^3

Jan 27, 2011
 You are standing beside a road watching cars pass by. The probability that you see a car pass by in 1 minute is 1/4. What is the probability that you see a car pass by in 30 seconds?8 Answers1-sqrt(3)/2why is thislet p=probability that you see a car in 30 seconds p(see car in first 30 seconds)=p p(see car in second 30 seconds)=p p(see car in the first 60 seconds)=2p-p^2=1/4 solving you get p=1-sqrt(3)/2 (reject 1+sqrt(3)/2 since it's over 1)Show More ResponsesI have a question on this solution: 1-(1-p)^2 is the probability of seeing at least one car, not the probability of seeing a car.You can also solve this using exponential distribution. From the question, you can deduce that the distribution has to be memoryless and hence there has to be a constant rate per unit time for the event to occur. Let the probability per unit time of a car passing by be p. Then from the given information 1/4 = 1 - e^{-p*T} The required answer is e^{-p*T/2} which gives the answer as reported above.Minor correction in above. The required answer is 1 - e^{-p*T/2}ans 1/2 as the person sees car in 15 sec of each 1 minute if we divide 1 minute into 4 parts (60/4 = 15 secs) s the probablity of seeing car now we are asked in 30 sec . the rate of moving of car will not change it will still continue to come at a rate of 1 in each 15 sec so the ans for each 30 sec would be 1/2 if we divide 30 into 2 parts . so in 15 sec one car is left .but for next 30 sec no car is going to come then itls probability would be 0 . now the ans is tricky which 30 secs are asked , the 30 sec in which car is seen or in which it is not seen by the man1 - sqrt(3)/2 is the wrong answer

Jun 7, 2010

Sep 19, 2012
 “Given the numbers 1 to 1000, what is the minimum numbers guesses needed to find a specific number if you are given the hint "higher" or "lower" for each guess you make.”6 AnswersI found 1 of the questions on their test here: http://www.math.ku.dk/~rolf/teaching/mfe03/mfe03.soln.pdfIs this 10? 2^10 > 1000 and 2^9 < 1000?The answer is 1. Read the question carefully. It asks for the minimum # of guesses for a number between 1 and 1000. If you guessed the # right the first time, you don't need to guess again.Show More ResponsesCrazy is crazinessidt9