Use Baye's formula: b=p(rain over weekend)=1-p(no rain over weekend)= 1-(.4*.2)=.92 a=(p rain on saturday)=.6 p(b given a)= 1 since if it rained on sautrday, it had to rain overhe weekend so p(a)*p(b given a)/p(b)=.6/.92=.65=p(a given b)=p( rain on saturday given it rained on the weekend)
0.65 > 0.5 dude... think again
The first answerer is correct I think. One of the following happened: It rained on Saturday only: 0.6 * 0.2 = 0.12 It rained on Sunday only: 0.4 * 0.8 = 0.32 It rained on Saturday and Sunday: 0.6 * 0.8 = 0.48 Add these up: 0.92 total of it raining over the weekend. But the question is stated that it's given that it rained over the weekend. So: Pr(Saturday) = (0.12 + 0.48) / 0.92 = 0.6 / 0.92 = .652 (roughly 2/3)
I think the correct answer is 11. Pulling out three could mean three black or three white. Pulling out 11 means, for sure, you get 10 of all the black OR white ones (since there are only 10 of either one) and 1 of the opposite ... making a pair.
@Steve. A matching pair means two of the same color. When does one black and one white sock make a matching pair? If you came to work like that, I would fire you.
The previous answer is kind of confusing, so here is my attempt to clarify: WACC = (E/(E+D+P))*Re + (1-Tc)*(D/(E+D+P))*Rd + (P/(E+D+P))*Rp Where E is the market value of the firm's equity (common stock) D is the market value of the firm's debt P is the market value of the firm's preferred stock (if it has any) Tc is the corporate tax rate, because the interest paid on debt is tax-deductable WACC is also an appropriate rate at which to discount the future cash flows of the firm.
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