Design Engineer Interview Questions
A design engineer evaluates and improves different aspects of a product, such as safety and functionality. When interviewing for this job, expect to answer scenario-based and technical questions. Get ready to speak about your experience with product design, communication, and attention to detail.
Top Design Engineer Interview Questions & How To Answer
Here are three top design engineer interview questions and how to answer them:
Question #1: What types of software and devices have you used during your career as a design engineer?
How to answer: A design engineer should be skilled in industry-specific software and devices. Demonstrate to the hiring manager that you have technology expertise by specifying the computer-aided design (CAD) and computer-aided engineering (CAE) software you use. Additionally, describe any technologies specific to your design engineering career, for example, the MOSFET circuit design for a circuit design engineer position.
Question #2: How do you manage your time when working on several design engineering projects?
How to answer: Address this personality-based question by identifying the techniques you would use to organize your time in this scenario. For example, you can discuss creating timelines, scheduling and prioritizing tasks, and meeting deadlines.
Question #3: While working on a design engineering project, you experience a setback. How do you stay on track?
How to answer: With this question, the hiring manager is evaluating your motivational abilities. Talk about a strategy you use to stay motivated. Try to give an experience-based answer, such as the self-motivation technique you used when you misunderstood a design request parameter provided by the research and development team.
What are the different ways you can you tell if this part is steel or aluminium.
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By far the easiest way is to test for material properties. -density -hardness -modulus of elasticity I would choose hardness. Strike each item with an equal force, which one deforms more? Thats aluminum. You could probably pull this test off with a hammer. The simplest solutions is always the best. Less
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Simple methods would be density (feeling the mass of the object), surface finish (color, texture). If coated that may give you the answer i.ie anodized would indicate aluminium. For more information I would go for EDX( Energy-dispersive X-ray spectroscopy) and possible a cross section to look at the grain structure. Less
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Density, thermal conductivity, electrical conductivity, strength, harness
What are 5 different variables of a coil spring you can change to affect spring force?
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5 different variables that can affect the springs force. 1.) Wire length 2.) Coil pitch 3.) Wire cross-sectional shape 4.) Material of the coil 5.) Coil diameter Less
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1. WD 2. OD 3. Active coils 4. Material 5. Free Height
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Material, wire diameter, wire cross sectional shape, coil diameter, coil length
If you have a cantilevered beam with a load at the unsupported end, what can you change about the beam to mitigate the effect of the load.
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Reduce the length, increase the thickness, change the material to one with a stronger young's modulus (just have to be careful about the tradeoff between material density and stiffness). Less
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Taper it.
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What is the weight of the load? What is the weight of the beam? Does the beam even need to be changed? Certainly you can shorten the beam , you could also turn the beam 90 degrees so the taller end is pointing upwards. There are questions that should be asked before any answers are given. Less
need to join tomorrow are you ready?
13 Answers
Given a string find the first non-repeated character.
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@Rajiv : Your solution is completely wrong. It will fail for input of "aaa" Reason: on first check, you insert "a". On next check you remove it. On next check you again insert it and return that as your answer, even though it was repeated thrice. Less
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program to find first non repeating character in a string c# - three ways
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My python implementation: def firstNonRepeatingCharacter(inputString): hashmap = {} for x in inputString: if (x in hashmap): hashmap[x] = hashmap[x] + 1 else: hashmap[x] = 1 for x in inputString: if (hashmap[x] > 1): continue else: return x return "No nonrepeating character found" Less
Basic MOSFET, CMOS questions were asked.
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Hey, you should feel glad that you weren't accepted by them. This company is very cheap and doesn't treat its employees well. Less
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I guess...but it is not the right way to interview candidates don't you think?
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That's really sad. They should rather go with Skype or any other means to interview. Now,. I have got an on-site call for Digital circuit design and I am giving it a serious thought 🤔 Less
There is a refrigerator in a perfectly insulated room. The door is then opened. Is it an open or closed system? After a long time has passed, has the temperature in the room increased or decreased?
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It is a closed system as electricity is adding energy into the room. After a long time passes, the temperature increases as there's energy going in, but not leaving. Less
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It's a closed system. Since the efficiency of heat transfer is not 100%, will generate heat and eventually heat up the room. Less
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Since there is energy going into the room, it is open system without mass transfer. The room temperature will increase. Less
Create a 8 input AND gate using 3 4:1 muxes
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Without an enable bit on at least one of the mux's the maximum inputs would be 7. Less
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I don't see it being possible with three standard 4-1 muxes... Using 4, this question is straight forward... The two selects of each mux are your 8 inputs... tie out put of each mux to the (11) case input to the mux. Less
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We need 3 4:1 MUX and a And gate. Are we allowed to use 'and' gate?
Show me the back of an iPhone and asked me how it might have been manufactured.
8 Answers
design a full adder with 2-1 mux
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full adder can be got by 2 half adders and one OR gate; one half adder can be got by XOR, AND. Therefore, we need only OR, AND, XOR. All these three gates can be got by using MUX.? Less
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Can be implemented using 8 Muxes.
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sum = a xor b xor cin carry = (a xor b) cin + ab You can easiy make XOR, OR AND, NOT using 2:1 mux. So 8 mux ?!? Less