Digital design engineer Interview Questions

I am not from Analog background but my analytical ability lead me through to answer it perfectly.

Cool question!

Very cool question

You got no offer because they prefer to hire their buddy. and only few y of thejob ads actually a real hiring

You are lucky you did not pass the interview. It is a terrible hostile working environment if you are not a part of the persian or korean gang. Also, the HR lady has been monitoring this glassdoor like a hawk, because she got not much to do everyday than watching people to make sure they do 8-hour a day like walmart employees.

0-100 have constant addition. add the numbers in the array and subtract it from the constant sum.

Assuming that a number only appears once, find the sum and subtract from the total possible value (1+2+3+....+100) and subtract to find the missing number. But it would be smart to ask if a number can appear multiple times or not since that may increase or decrease the complexity of the problem, but shows that you're really thinking about all the problem parameters.

when the flops goes in to an unknown state ( either 1 or 0)

The key in these questions is to cover the fundamentals, and be ready for the back-and-forth with the interviewer. Might be worth doing a mock interview with one of the Texas Instruments or ex-Texas Instruments Digital Design Engineer experts on Prepfully? They give real-world practice and guidance, which is pretty helpful. prepfully.com/practice-interviews

Two registers storing last two numbers in sequence with adding circuit muxed with the enable signal. Combinational output from mux. Answer should be in verilog code.

This is actually another way of asking: what is the difference of blocking and non blocking assignment. and the key point in this question is to use the non blocking assignment

If I understand it correctly, the question is asking about prefix code (either Huffman or Shannon-Fano). Ignore me if I understand the question incorrectly. Assume from 1 to 3 bits are used to encode 4 codewords using Shannon-Fano encoding, and the codewords are {0, 10, 110, 111}. the decoder will have to translate the received messages into 2-bit binary codewords {00, 01, 10, 11}. A state machine will look as follows: Reset and Start don't have to be separate states if we assume that the input is continuous and has no interruptions: (Reset) -> (Start) -> (S0) -?> (S1) -?> (S2) -?> (S3) -> (Reset) where -?> represents a conditional jump to either the next state or to the (Reset) state. If the conditional jump is to the (Reset) state, the output is set according to the table: S0 ==> 00 S1 ==> 01 S2 ==> 10 S3 ==> 11 (always output this value in this state) (-?>) means: if (1 is received) go to next state else output the appropriate value and goto (Reset)

There's a lot of elements to typically cover in these questions, clarifications, scoping, making sure you're answering the actual question the interviewer is looking for you to answer, etc. Could be worth doing a mock interview with one of the Prepfully Qualcomm Digital Design Engineer experts... they've worked in the role so they clearly know how to get through the interview. prepfully.com/practice-interviews

MOESI is a cache coherency protocol- like the MESI (Modified, Exclusive, Shared and Invalid) but with an "Owned" state. Modified: Data is recent (and has been modified!) and this data is held by no other processor or the memory. This data is 'dirty'. Exclusive: Data is recent and present only in the current cache and the memory holds a copy as well. No other processor holds this data. Shared: Other caches may also have this data and the data matches memory. This data is 'clean'. Invalid: The data is invalid or incorrect. Owned: The Owned state signifies that the data is Modified as well as Shared. While the data must be still written to memory, this can be delayed since there is no need to write the modified data into memory before sharing it.

This is ofcourse, for a Write-back Cache!