Broadcom Interview Question: how to generate a clock divid... | Glassdoor

Interview Question

ASIC Design Engineer Interview Irvine, CA

how to generate a clock divide by 3

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Interview Answer

4 Answers

0

Assuming that input clock is square wave and 50% duty cycle,
Method 1: Clk / 3 is equal to Clk / (6/2). this means fist divide by 6 and multiply by 2.
dividing by 6( use two DFF(D is tied to Q_b and it is connected to clock of 2nd DFF).
multiplying by 2( create some delay and XOR the two signals(the signal after dividing by 6 and its delayed signal), But it's hard to make the output clock have 50% duty cycle due to precise delay control. so alternative method 1 is first multiply by 2 and divide by 6.
Method 2. Use 2 edge counters(one for rising edge and the other for falling edge)
draw the state machine that goes (back) to toggle state when both counters become 2.

Jong on Mar 8, 2013
0

Sorry, Method 1 is incorrect.
the possible method 1 is to delay the input clock and XOR the input clock and its delayed one(delay doesn't need to be precisely half period of input clock, which is good) then use a single rising edge counter to toggle when it counts 3 rising edges. this is glitch-free

Jong on Mar 8, 2013
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Please refer to:
http://www.eetimes.com/document.asp?doc_id=1202359

Ming on Jan 7, 2016
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Sorry above is wrong link. correct link:
http://vlsiwizard.blogspot.com/2008/01/design-clock-divide-by-3-circuit-with.html

Ming on Jan 7, 2016

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