Manager Interview Questions in Hyderabad, India | Glassdoor

Manager Interview Questions in Hyderabad, India

"Companies count on managers to make smart team decisions and oversee group members in order to maintain deadlines and keep operations running smoothly. Be prepared to answer several situational questions that will evaluate your time management skills, problem solving abilities, and ease in leading a team. Employers will also expect you to be well-versed in products and operations, so make sure to brush up on the department's relevant work."

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Program Manager at Microsoft was asked...

Jul 5, 2012

Jul 31, 2013
 what is angle between hour hand and minute hand in clock at 4:20 ? what is biggest conflict management you have handled in your work place13 Answers4:20 - ANGLE WOULD BE 120 CIRCLE IS 360 DEGREES , EVERY 5 MINUTES = 30 DEGREESIF min's hand rotates for 360 deg, hr's hand rotates for 30 deg - so for 60 min - hr's hand rotates for 30 deg. For 1 min it rotates for 0.5 degree. Hence, for 20 min it rotates for 10 degrees. The angle between hr's hand and min's hand should be 10 deg.have you ppl looked at an analog clock recently it is 0 or 360 degreesShow More ResponsesThe angle between hour and minute hand in 4:20 is 10 degrees. For a minute, the hour hand rotates by 30/60 = 1/2 degrees. hence, for 20 minutes it rotates by an angle of 20*1/2 = 10 degrees.The formula is 180 - | 180 - | m * 6 - (h * 30 + m * 0.5) |Heres the complete formula.. for better understanding.. ABS is absolute value 180 - ABS (180 - ABS ( m * 6 - (h * 30 + m * 0.5) ) )An analogue clock is degrees. 360/12=30 degrees per hour 360/60=6 degrees per minute So for 4 hours - 30*4=120 degrees For 20 mins - 20*6=120 degrees therefore, Answer is zero20 minutes is 1/3 (20/60) of the way around the dial, 4 o'clock is also 1/3 of the way around a clock (4/12), so they are perfectly aligned and the angle between them must be zero.There are two approaches to this question: - If you assume the hour hand stays put and only moves every hour o'clock (which is a simplification, but a reasonable one), then the angle is 0º. - If you assume the hour hand rotates at a constant angular speed, then the answer is 10º. Since there's 360º / 12 = 30º between hours: + The minute hand points at 4. That's 30º x 4 = 120º. + The hour points slightly past 4. Since a third of the hour has passed (20' = 60' / 3), then the minute hour has moved a third of the way between hours. Hence the hand is at 120º + 30º / 3 = 130º. The difference between the two hands is 130º - 120º = 10º So I guess you get some poits for saying 0º, more points for saying 10º. My question is, did you get to use pen and paper, or you had to answer on the spot?in every 60 minutes hour hand moves 30 degrees. so at 14:20 ( it means that 20 minutes have past since last turn) hour hand moves 20*30/60 = 10 degrees so the answer is 10 degrees...360/(12*3) = 10010 degrees

Jun 10, 2012
 How many ways that you can choose 3 desserts from a menu of 10?7 AnswersC (10, 3) = 120 - This is very simpleJust to clarify: the original reviewer's answer - C(10,3) - is indeed incorrect. More specifically, C(10,3) represents a number of ways to pick 3 DISTINCT desserts. The problem statement does not suggest that the desserts should be unique; moreover, it's very natural to order three identical desserts! I believe the correct answer to be a sum of C(10,3) /* number of ways to pick 3 distinct desserts */ + 10 * 9 /*number of ways to pick 2 matching and 1 distinct dessert */ + 10 /* number of ways to pick 3 matching desserts */ = 220if repetition is allowed, its 210 ways if repetition is not allowed, C(10,3) = 120 waysShow More ResponsesIf order matters (it would to me if I were eating them), and repetition is allowed, the answer would be 1,000 since you can choose any of the 10 for the first, second and third dessert resulting in 10 X 10 X 10 possible dessert sequences.10x10x10 = 100010*9*8 = 720 combinations45 I suppose

Operations Manager at Amazon was asked...

Apr 30, 2013
 If in a room there are 10 persons and if each person has to shake hands with all other then total how many hand shakes will be there15 Answers10C2=45should be 90Forgot 90 Milk ShakesShow More Responses10(10-1)/2"Each other" leaves this very open-ended; that depends on if A shakes with B or A shakes with B & C, OR if A shakes with all the other nine, etc. I would say the answer would have to be one of two: 10 or 100. If each person chooses only one to shake with, it would be ten. IF each person shakes with everyone there, all ten, it would be 100. Since this question is pretty vague, Some people may come to the conclusion that the answer is Either 90 assuming everybody stayed to shake hands with each other meaning the first person shook hands with 9 people and the 2nd person did the same etc etc bringing it to the conclusion that you got 90 handshakes. Another answer towards for people would be 45 being that the first person gave a hand shake to 9 people and then left and then the 2nd person gave a handshake to 8 people n then left etc and etc making it 9+8+7+6+5+4+3+2+1=45.simply formulas: n*(n-1)/2 (n-1)*(n/2)Lock in 90 thanks455n(n-1)/2 = 10(10-1)/2 = 45 If there are 10 persons, the first shakes hands nine times, the second eight times (already shook with first person), and so on. In other words, 9+8+7+6+5+4...1. n(n-1)/2 2. 10*9/2 3 90/2 4. 45If you say 90 you are including the repetetions. If first person shakes 9 times, the next one requires only 8 shakes. So it goes like, 9, 8 ,7 ,6...1. Can use the formula n*(n-1)/2/. So we get only 45 shake hands. It is similar to no of squares in the chess board. There squares will apply.9Show More Responses45If one person is lefty?

Operations Manager at Amazon was asked...

Apr 30, 2013
 If u are running at 10km/hr and anothet person is running st 20km/hr then in which round u both will be at same point11 Answers44 is wrong answer to this question. Its answer for next question. Posted here by mistakeNo matter what size track they run on, they will meet at the starting line every two laps.Show More ResponsesWith slower person's perspective, they will meet at starting point each round. Person running 10 km/hr, will complete one round, while the other person will complete two round during same time.You are assuming that the track is exactly 1KM in length. Most tracks are not that, what are they 440?Yes, with reference to the slower runner, they'll meet every round and with reference to the faster runner, they'll meet every alternate round.There is not enough infomation here. You really do need to know the length of the track to determine future meeting points.every round for the slower runner.at the end of second round (w.r.t to the person with 20km/hr speed).From 20kmph perspective Every alternative round they will meet at starting point , From 10kmph perspective every round they will meet at starting point.2nd round

Apr 30, 2013

Apr 15, 2010

Apr 15, 2010