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Network Engineer/Systems Administrative was asked...December 8, 2011

How do you handle irate clients that are having technical trobules and need to work immediately.

4 Answers

You tell them, you understand the frustration and you will immediately send someone to fix the issue. You do basic troubleshooting and if it doesn’t work, send tech support. Less

Approach the situation with 'we' working on the issue. Know that your are there to help solve this and act towards that, being calm and accurate towards solution. Even if the solution is that you will have to find out more and have to return to solve this issue. Less

Ask for the ip address, then ask if it is an on or near-air emergency. Ask for the symptoms and if others are experiencing the same problem. If no one else is then have them jump on another pc if possible/feasible. Remote into the pc or tx the ip to the relevant trouble-shooter. Less

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What are the 6 TCP flags?

2 Answers




What's the difference between block code and convolution code?

2 Answers

Block code code information in blocks while convolutional codes convolve information bit sequence Less

In block codes, information bits are followed by parity bits. In convolution codes, information bits are spread along the sequence. Block codes are memoryless whereas Convolution codes have memory. Convolution codes use small codewords in comparison to block codes, both achieving the same quality. Less


Given a very large existing network with thousands of external connections, how would you add an additional few hundred connections?

2 Answers

someone building networks with thousands of external connections considering anything but 10G, 1G at minimum... doesn't understand COGS.... the name of the game is $0.000xxx/Mbps.. which you are not going to get with anything but ethernet. Less

Think it through, out loud. Walk through your options- don't just pick one. DS3, metro-E, SONET, etc. Less

The Emirates Group

How long do you plan to work here?

34 Answers

4 years

As long as possible

For ever

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Aryaka Networks

tcp and udo difference to explain on board with examples, what is ping,traceroute, 7 layer workings, vlan, subnetting

20 Answers

Topic they asked me was distance education vs college education, they will check grammar not accent. No matter how strong your technical skills are, they will allow to 2nd round oly if you clear GD. be prepared. Best company as for fresher. I had 4 rounds- gd, face to face ( hr kind), and then 2 technical rounds. one of my friend had another technical round, totally5 rounds. So final point, they need technical strong guys...i mean it. In Interview they will ask you everythin regarding network(do read wan optimization too), check interviews question which i posted. As your ccnp certified it would be piece of cake for you. do drop mail if need any other info. three of my frnds attended that so have clear idea on interview process. all de best Less

Nope. no sign at all. In another company interview, met another guy who attended interview at aryaka networks on the 3rd june. He told me same answer :D. you better search for another job, i did like that and got selected to another company, don't just wait for that. If you want confirm, u can ask HR through linkedin (if you remember HR name). or paste your mail id il send the HR linkedin link. Less

did they told you that hr will contact you after 4 rounds or something else , i got interviewed too and they told me that , i need to know ,it will be really helpful for me if you could tell me what they said. thanks Less

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Where do you live?

14 Answers




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All questions are mentions in the review and practice following coding questions for sure on leetcode.

14 Answers

3. convert the sentence to the modified pig-latin/goat-latin language. Complexity Time: O(n) + O(5) + O(k(k+1)/2) Considering total n characters in sentence. m characters/word O(n): Reading compelete sentence O(2): For vowel. Append ma O(3): For consonant. Append ma and 1st character 1+2+3+... k words = k(k+1)/2 Space: O(n) + 2O(m) + O(5) O(5): unordered_set of vowels 2O(m): Storing 2 word O(n): Storing complete sentence Code #include #include #include void AppendA(std::string& strWord, int& count){ int i = 0; strWord += "ma"; while(i++ us = {'a','e','i','o','u'}; //1st Letter is Vowel if (us.find(std::tolower( != us.end()) { strWord = strParsed; AppendA(strWord, ++count); } else //consonant { strWord = strParsed.substr(1,strParsed.size()); strWord += strParsed[0]; AppendA(strWord, ++count); } } int main(){ std::string strInput = "Adam wants to go to the university"; std::string strOutput, strWord, strParsed; int count = 0; for (auto& i:strInput){ if (i == ' '){ Process(strParsed, strWord, count); strOutput += strWord + ' '; strWord = ""; strParsed = ""; } else //Store word in strParsed { strParsed += i; } } Process(strParsed, strWord, count); strOutput += strWord ; std::cout<<"Converted string="< Less

1. You receive a vector/ array and 2 numbers, eg 2 and 5. Between those 2 positions in the vector (2 and 5) you have to reverse the order of the elements. Code #include #include #include using vec = std::vector; using itr = std::vector::iterator; int main(){ vec v = {1,2,9,8,4,5,23,5,252,445,677,5}; //Find position of 2 itr it1 = std::find(v.begin(), v.end(), 2); //O(n) //Find position of 5 itr it2 = std::find(v.begin(), v.end(), 5); //O(n) std::reverse(it1+1, it2); //O(n) for (auto i:v) std::cout< Less

2. Count words and output top n Complexity n: number of words Space map=O(n), priority_queue = O(k). Since we only create queue of size=k, output vector = O(k) Time Creation of map=O(n), Creation of priority Queue=O(n), Creation of output vector=O(k) Code #include #include #include #include using VS = std::vector; using mypair = std::pair; class Solution { public: VS topKFrequent(VS& vsWords, int k) { VS vsOut; std::priority_queue pq; std::unordered_map um; // for(const auto i : vsWords) //1 um[i]++; //um[key]=value; //um[i] = um[i]+1 for(const auto i:um){ //2 pq.push(make_pair(-i.second,i.first)); if (pq.size() > k) pq.pop(); } while(not pq.empty()){ //3 vsOut.push_back(; pq.pop(); } for(int i = 0; i < vsOut.size()/2; i++) //4 std::swap(vsOut[i], vsOut[vsOut.size()-i - 1]); return vsOut; } }; Less

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a detailed troubleshooting scenario for VPN was asked. a site-to-site VPN, user from one site cannot get to a resource on another site.

8 Answers

There was no one answer for this, and since I didn't know much about vpns, the interviewer guided me through the possible answers! Less

Hello, Can anyone tell me the best link to study troubleshooting scenarios from?

#sh vlan brief

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How does STP does it know who will control everything?

5 Answers

It disables redundant paths and only leaves one broadcast path in a mesh network. It then enables a previous blocked path if one of the primary links becomes disconnected. This creates a network that won't cause broadcast storms but still provide redundancy. Less

STP operates at the Data Link layer of the OSI model which prevents traffic loops. STP chooses only one root switch/bridge, out of which all data paths span out logically getting the data to the target the quickest and detect and correct link failures when a switch/bridge fails...STP stands for Spanning Tree Protocol. The root is chosen based on its BID( Bridge ID) which is the combination of a 2 byte priority field and the bridge/switch MAC address....Since all switch/bridges on the network start out with the same priority, the one with the lowest MAC address becomes the root bridge. Less

STP is basically used for loop prevention and to prodive redundancy. Devices participating in STP perform a root bridge election process. Device having the lowest priority will be choosen as the root bridge. If every device participating in STP have the same priority value, device with the lowest mac-address becomes the root bridge. The root bridge will be responsible to make th overall traffic flow decision on the LAN. Non-root bridges use a lowest cost path to reach the root bridge. This cost is dependent on the interface speed. Topological changes downstream from the root bridge is communicated to the root bridge. Less

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