Seismic Imager Interview Questions | Glassdoor

# Seismic Imager Interview Questions

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Seismic imager interview questions shared by candidates

## Top Interview Questions

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### Junior Seismic Imager at CGG was asked...

Feb 4, 2011
 how many 1s are there from 1-100 8 Answers 23 19 --- 1, 1*, *1 21 1s including 100 Show More Responses 20 100-9*9+1+1=21 C(2,1)*9 + 2 * C(2,2) + 1 (the one from 100) = 21 20 1

### Seismic Imager at CGG was asked...

May 1, 2012
 What is the most important thing you look for in a job? 3 Answers Boilerplate, I know but I wasn't expecting it with this interview. What were the main math areas that they based the questions on? I know you mentioned statistics - by that do you mean probability mainly? Yes, probability. It's all math that you should have gotten in high school or your first year in college.

### Junior Seismic Imager at CGG was asked...

Oct 21, 2014
 some physics question : a man was going up and down on the stairs, asking how long it will take or stag like that 1 Answer it was not a hard question, just listen carefully

### Seismic Imager at CGG was asked...

Jul 17, 2012
 what is area of a hexagon? 1 Answer If you are given the length of a side and apothem, then Area is the half of the product of perimeter and apothem. Area of a Hexagon = 1/2*6*l*a Here l is the length of a side a is the length of apothem.

### Seismic Imager at CGG was asked...

Jan 16, 2014
 1-10000, integers with "7". 5 Answers There two ways, second way being more efficient if the range of the numbers is big: 1) Determine the integers containing 7 and count the number. For instance; From 0-9, there is only 1, i.e. 7 from 10-19, there is only 1, i.e. 17, . . from 60-69; there is only 1; i.e. 67, from 70-79, there are 10, i.e. 70, 71, ..79 .. from 90-99, there is only 1; i.e. 97 So between 1-100, there are 9*1+10 integers containing 7. Do this for hundreds and thousands also, You should get 9*(9*(9+10)+100)+1000=3439 2) Write every number between 0-9999 in the form abcd. For instance, 12 is 0012. The number of integers between 0-9999 inclusive not containing 7 as a digit is 9*9*9*9=9^4=6561. Therefore, we counted 0 but not counted 10000. Therefore, there must be 6561 integers again between 1-10000 not containing 7 as a digit. So, there must be 10000-6561=3439 integers between 1-10000 containing 7 as a digit. This question is equivalent to how many at most four digit numbers can you make with at least one 7 included? 1. one 7 included: C(4,1)*9*9*9 2. two 7 included: C(4,2)*9*9 3. three 7 included: C(4,3)*9 4. four 7 included: C(4,4) 4*9^3+6*9^2+4*9+1= 3439 It can be 10000 - 9*9*9*9 = 3439. Show More Responses Shoudl be 3438 since 10000 also does not contain 7 There are 9999 numbers from 1 to 10000, so it is 3439.

### Seismic Imager at CGG was asked...

Jul 6, 2011
 Four digit number, when placed in reversed order, is four times of the original. What is it? 1 Answer assume the four digit number is ABCD and A > 0. so 4 * (ABCD) = DCBA First think about A. What can A be ? Can A =3 ? No. Since 4 *( 4BCD) is a five digit number. S A is 1 or 2. Can A be 1 ? The answer is No. Since DCB1 can not be divided by 4, DCB1 can not equal to 4 * (1BCD) So A = 2 A little thinking more will give that D = 8 Then solve this equation 4 * (1000* A + 100* B + 10 * C + D) = 1000 * D + 100 * C + 10 * B + A finally we can get B = 1, C = 7 So the number is 2178

Feb 4, 2011

### Junior Seismic Imager at CGG was asked...

Apr 16, 2011
 Why have you taken subjects outside this field?

### Seismic Imager at CGG was asked...

Feb 16, 2015
 What is Q value?

### Seismic Imaging Geophysicst at CGG was asked...

May 23, 2011
 The interviewer showed me a geometric shape and asked me to divide it into 4 parts of same area.
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