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No, We should not release the application with critical defects. Make sure the management team how the impact of the critical defects in the application without fixing and quality of the product not guaranteed. Less
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Decline to release and ask if I can have time to fix the defects
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Meet online meetings code for the information
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Good learn and devlop every challenge and fect
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Learn to all process that's improv to our work
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yes, cause i look for a job, i"m not looking for a position. to start in any job everybody start in above position before they overcome the high position, that they want. Less
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Are you high?
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"I'm sorry, no, it is not okay."
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I am very interested & i am redy to give all Success & Reputation with my hard work for this company sir. Less
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I am currently employed In Jaguar Europien Tap Fittings Company,but now I am very interested to join as a Sales Consultant or Customer Relations Success Executive in our Jaguar Land Rover Car Company - Japan sir. Less
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I am currently employed,due to some fluctuation of current job business I am very interested to join In Japan Job sir.Because I am very interested to do job In Japan. Less
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That is an incorrect answer. The boat can not hold more than 2. 1M + 1C take the boat and leave 1C on the other side. 1M (left in the boat) goes back and takes 1C. They cross and 1M stays on the other side. 1C (left in the boat) goes back and takes 1M and drops him off on the other side. 1C (left in the boat) goes back and takes the last 1M and drops him off on the other side. 1C (left in the boat) goes back and takes the last 1C and cross the river. Less
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The correct answer to this question is a bit more complicated than the ones currently posted. DeerJohn's answer fails to solve the problem because it violates the constraints of the boat. Henry's answer unfortunately leaves us with a situation where 1 Missionary and 1 Cannibal are in a boat together headed to the opposite shore where 1 cannibal is already waiting. Thus when they arrive the two cannibals eat the outnumbered missionary in the boat. The boat does not provide any sort of invincibility or defense. To correctly solve this problem it will take 11 total trips from bank to bank. I'll try and diagram it below, A trip will be defined as any attempt to cross the river. START: BANK1: mmm ccc | BOAT: | BANK2: TRIP1(crossing): BANK1: mm cc | BOAT: mc | BANK2: TRIP2(returning): BANK1: mm cc | BOAT: m | BANK2: c TRIP3(crossing): BANK1: mmm | BOAT: cc | BANK2: c TRIP4(returning): BANK1: mmm | BOAT: c | BANK2: cc TRIP5(crossing): BANK1: m c | BOAT: mm | BANK2: cc TRIP6(returning): BANK1: m c | BOAT: mc | BANK2: m c TRIP7(crossing): BANK1: cc | BOAT: mm | BANK2: m c TRIP8(returning): BANK1: cc | BOAT: c | BANK2: mmm TRIP9(crossing): BANK1: c | BOAT: cc | BANK2: mmm TRIP10(returning): BANK1: c | BOAT: c | BANK2: mmm c TRIP11(crossing): BANK1: | BOAT: cc | BANK2: mmm c END: BANK1: | BOAT: | BANK2: mmm ccc Less
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All 3 missionaries should go across, leaving two on the opposite bank. One missionary returns to retrieve 2 cannibals, leaving then with the two missionaries already on the opposite bank, then returns for the last cannibal. Less
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There were two followup questions to this. a) What if there are lot of zeros after the sum is 10. E.g. 505000000 - what would it return? b) what if we allow negative numbers. For example 5,5,-6,6,0,0 We also discussed its time complexity. Less
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The following should work. cheers! public int[] calculateSumSet(int[] inputArray, int desiredSum) { for (int stratingIndex = 0; stratingIndex < inputArray.length; stratingIndex++) { int sumOfSubArray = -1; int endingIndex = stratingIndex; do { sumOfSubArray = getSum(inputArray, stratingIndex, endingIndex); if (desiredSum == sumOfSubArray) { return subArray(inputArray, stratingIndex, endingIndex); } endingIndex++; } while (endingIndex < inputArray.length);//&& sumOfSubArray < desiredSum } return null; } private int getSum(int[] inputArray, int stratingIndex, int endingIndex) { int retValue = 0; for (int i = stratingIndex; i <= endingIndex; i++) { retValue += inputArray[i]; } return retValue; } private int[] subArray(int[] inputArray, int stratingIndex, int endingIndex) { int[] retValue = new int[endingIndex - stratingIndex + 1]; int j = 0; for (int i = stratingIndex; i <= endingIndex; i++) { retValue[j] = inputArray[i]; j++; } return retValue; } Less
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Hi, What made you say that "Talking about TDD in a company where tests virtually do not exist is a big no-no"? Did you talk about it in general or did you make your presentation on/about TDD? What do you recommend for future candidates? --prospective candidate Less
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I answered nearly all questions that is why I got selected
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If Someone your Caleague not listening and not achieving his target.. You have to spend some time with your Caleague and work together.. After that he understand self.. Less
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If someone ur Caleague not leation and doing achieving target.. U have to spend some to ur Caleague and work with him next he understand.... Less
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I discribed the situation difficulty and explained the solutions and how I acted till I reached a pleasent feedback Less