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In a series circuits with , what is the voltage across capacitor two. The point of this was to show that the voltage depends upon the value of the other capacitor, and this relates to what happens in a NAND gate as the signal switches from positive to negative.

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Let us assume that two inputs A and B acts as a switch .These two switches A and B, are connected in series .So,as switch A is closed,output depends on second switch.the output is inverse of second switch value.This is the operation of NAND gate.Similarly,in case of voltage divider circuit,the output of second capacitor depends on first capacitor.[check impedances ]

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