Yes, the sequence: √11, √55, 5√11, 5√55, 25√11 is an arithmetic progression (AP) with a common difference. To confirm: 1. √55 - √11 = 4√11 (difference between 1st and 2nd terms) 2. 5√11 - √55 = 4√11 (difference between 2nd and 3rd terms) 3. 5√55 - 5√11 = 4√11 (difference between 3rd and 4th terms) 4. 25√11 - 5√55 = 4√11 (difference between 4th and 5th terms) The common difference (d) is: d = 4√11 The sequence follows the AP formula: an = a1 + (n-1)d where: a1 = √11 (first term) d = 4√11 (common difference) n = term number Well done! Would you like to explore more properties or find the nth term?