I applied online. The process took 4 weeks. I interviewed at AKUNA CAPITAL (Chicago, IL) in Sep 2024
Interview
4 Stages: Resume Screen -> Technical Online Assessment asking math competition style questions -> 1st Technical Round -> Final technical round -> Offer
I made it to the final round but botched the last question so I am not sure if there is a behavioral portion to the final at the end after you've optimized.
Interview questions [1]
Question 1
Estimate the value of pi using uniform random variables? Then they ask to optimize your implementation from there and compare it to some other methodologies
I applied online. I interviewed at AKUNA CAPITAL in Sep 2025
Interview
HackerRank Coding Test (3 problems, leetcode medium level), then Vidcruiter Test (need to verbally explain, serveral math, 5 min each), then Technical Phone Screen (normal brain teasers, probability etc.), then final round.
Interview questions [1]
Question 1
Problem Analysis:
A k-star consists of a center node and up to k arms (edges to other nodes)
We need to find the k-star with maximum sum of all its nodes
For each potential center, we choose the best neighbors (up to k) to maximize sum
Algorithm:
Build an adjacency list from the edges
For each node as a potential center:
Get all its neighbors
Sort neighbors by their values (descending)
Select up to k best neighbors
Calculate sum: center + selected neighbors
Return the maximum sum found
I applied online. The process took 3 weeks. I interviewed at AKUNA CAPITAL in Sep 2025
Interview
the first step is a leetcode like challenge, easy to medium difficulties. for 2 hour, there is enough time for you to solve them. if you pass the test cases, the following is the video math OA
You will receive an automatic OA (HackerRank Coding Challenge). If you pass, you will have a 5-minute video-recorded interview. The topics will be linear algebra, brainteasers, combinatorics, and probability. Make sure you review theories in linear algebra.
Interview questions [1]
Question 1
I got something similar to Leetcode's Maximum Subarray.