I applied online. The process took 2 months. I interviewed at Meta
Interview
The interview process was straightforward:
Phone screening -> coding interview -> 4 interviews (two coding, one behavioral, one system design interview)
The coding interviews were decent and not too difficult. They used a couple of tree and graph problems. They asked a lot about time and space complexity of the code I designed.
Behavioral was about my past experience and how I would act in a given situation.
The system design interview was a bit more difficult. I studied for this one as it was my first time doing it, but they threw me a curve ball and asked me to design a component I was not aware of from a technical standpoint.
Interview questions [1]
Question 1
Design an HTTP interpreter for a web browser (or something like that).
Generic LeetCode-style questions, many tagged as Meta, so extensive preparation is required to perform well in the technical interview. The experience varies significantly - some interviewers provide hints and guidance, while others expect candidates to solve problems independently with minimal assistance.
Spoke with interviewer over video conferencing. He was very communicative . He answered my questions. Asked me BFS question. A question that involved BFS search. Given a matrix, I am suppose to find a path from top left to down right.
Interview questions [1]
Question 1
A question that involved BFS search. Given a matrix, I am suppose to find a path from top left to down right.
The technical round hit me with a classic array manipulation problem: moving zeroes to the end without disrupting the order of non-zero elements. As I tackled it, I felt a wave of familiarity wash over me; I had just practiced a similar challenge on PracHub. The rest of the interview followed a straightforward path, with some easy behavioral questions sprinkled in. Overall, it felt very easy, but I wasn’t quite the right fit for what they needed, so I didn’t receive an offer.
Interview questions [1]
Question 1
Move zeroes in an array to the end while keeping non-zero element order, in place