# Software Engineer QA Interview Questions

Software engineer qa interview questions shared by candidates

## Top Interview Questions

### Software QA Engineering at CareFusion was asked...

You say that you work very well with developers to solve problems. How would you handle dealing with an extremely difficult engineer who won't acknowledge possible issues with his code and often won't speak with QA at all? 2 Answers1. Form a relationship by discussing work when there are no issues. 2. Acknowledge the difficulty and frustrations of the work. Find out what he/she wishes they could change and what would make their lives easier. 3. Ask if you can help in any way? 4. Ask him/her for help which allows them to show off their knowledge. Be appreciative, impressed and thankful. 5. Help them see how you can make them look good by eradicating bugs before customers and management ever see them. 6. Reinforce good behavior. 7. Make #2 happen if you can. Interviewers seemed to like the answer but were very doubtful any of that would ever work with the person they had in mind! Standards and QA must be everywhere in our life. So, there should be nothing personal. We all work for business. If QA finds that product's feature does not work as it supposed to, then QA Engineer must report it into a bug tracking system. Manager must assign this bug to SW Engieneer which is already a job task that must be done in timely manner. |

If you had a great idea to implement something new for a CA software product but management wouldn't take your word on it, how would you convince management to go along with your idea? 1 AnswerI would try to create a form of a prototype of said idea and present it along with taking ownership and compassion for the new feature. |

### Software QA Engineer at Apple was asked...

There are three boxes, one contains only apples, one contains only oranges, and one contains both apples and oranges. The boxes have been incorrectly labeled such that no label identifies the actual contents of the box it labels. Opening just one box, and without looking in the box, you take out one piece of fruit. By looking at the fruit, how can you immediately label all of the boxes correctly? 38 AnswersAll the three boxes are names incorrectly. SO the bax lebeled Apples+Oranges contains only Oranges or Only Apples. Pick one fruit from it. If it is Orange then lebel the box as Orange. So the box lebeled Oranges contains Apples and the remaining contains both. Label the boxes fruit. The key bit is "All the three boxes are names incorrectly" so the label on the box which fruit comes from will need to be changes to one of the other 2 labels. It can only be 1 of them (and it will be obvious when you have the fruit) then the remaining box (that hasnt featured yet)...Just swap that label with fruit box that was originally on the box which you took the fruit out of Thats hard for anybody to understand somebody elses explanation... eaiest way is to just do an example Show More Responses Swaz answer is almost correct however it does not work in all scenarios. lets assume: box 1 is labelled Oranges (O) box 2 is labelled Apples (A) box 3 is labelled Apples and Oranges (A+O) and that ALL THREE BOXES ARE LABELLED INCORRECTLY" Pick a fruit from box 1, 1) if you pick an Orange: - box 1's real label can only be O or A+O - box 1's current label is O - since ALL LABELS ARE INCORRECT then box 1's real label can not be O - box 1's new label should then be A+O by elimination - since ALL LABELS ARE INCORRECT - box 2's label is changed to O - box 3's label is changed to A - SOLVED 2) if you pick an Apple: - box 1's real label can only be A or A+O - box 1's current label is O - since ALL LABELS ARE INCORRECT then box 1's real label can not be O - this still leaves us with the choice between label A and label A+O - which would both be correct - FAILURE Solution: The trick is to actually pick a fruit from the A+O labeled box Pick a fruit from box 3: 1) if you pick an Orange: - box 3's real label can only be O or A - box 3's current label is A+O - since ALL LABELS ARE INCORRECT then box 3's real label can not be A+O - box 3's new label should then be O by elimination - since ALL LABELS ARE INCORRECT - box 1's label is changed to A - box 2's label is changed to A+O - SOLVED 2) if you pick an Apple: - box 3's real label can only be O or A - box 3's current label is A+O - since ALL LABELS ARE INCORRECT then box 3's real label can not be A+O - box 3's new label should then be A by elimination (not O) - since ALL LABELS ARE INCORRECT - box 1's label is changed to A+O - box 2's label is changed to O - SOLVED it only says you can't look, doesn't mean you can't feel around or smell the fruit you picked, easy deduction after you figure the first box out Sagmi is right, but did not give the full reasoning. "the bax lebeled Apples+Oranges contains only Oranges or Only Apples. Pick one fruit from it. If it is Orange then lebel the box as Orange." so far so good Now, the box labelled Apples cannot be the box containing only Oranges, you've just found that box, so it must contain Apples and Oranges. And in that case the other box, labelled Oranges, must contain only Apples. It's easier to draw it out. There are only 2 possible combinations when all labels are tagged incorrectly. All you need to do is pick one fruit from the one marked "Apples + Oranges". If it's Apple, then change "Apple + Orange" to "Apple" The "Apple" one change to "Orange" The "Orange one change to "Apple + Orange" If it's Orange, then change "Apple + Orange" to "Orange" The "Apple" one change to "Apple + Orange" The "Orange" one change to ""Apple" Since all 3 boxes are labled incorectly Start with the box Labled A&O. If Its apples than the box labled apples then the apple one is oranges and the oranges is O&A. Label each box "Apples and/or Oranges" and the all will be correct. This is very simple to resolve. I was asked the same question at FileMaker. Each box is incorrectly labeled. So you go to the box that is labeled "Oranges and Apples" and take one out. It doesn't matter what comes out because all that you know is that it is not AO. If you remove an Apple then move the Apple label to it. Since the Apples are already identified it is easy to resolve the rest. All you know for certain is that the other two boxes remaining are mislabeled. So the AO label goes on the box with the remaining label and that label goes on the Apple box as you have already assigned that. The end result is you only need to remove one piece of fruit to figure out the proper locations of all. Go down the road to HP. Maybe they are hiring. Some of these pseudo-problem solving questions like this are bunk. I was once asked why sewer covers are round and not square. I gave the correct answer without even hesitation and the interviewer seemed put off that I knew the answer. I didn't get the job but, in hindsight, no great loss. I prefer the questions (like the basketballs one from google) where you won't be able to give an accurate numerical answer but by explaining HOW you would go about solving the problem is all you need to do and MAYBE shows your aptitude for problem solving. Smell the box you opened. Step 1: Order the boxes by weight. Either apples weigh more than oranges, or oranges weigh more than apples. The mixed box will always be in the middle. Step 2: Open the first box, take out the fruit and look at it. Step 3: If the fruit is an apple, deduce that the middle is apple and oranges and that the third box is oranges. If the fruit is an orange, then deduce that the last is the box with the apples. Show More Responses Donna is the only one with any common sense. The problem with corporate America, is that it's run by a bunch of Bozos who over complicate things and have a narrow to zero vision on how to solve even the simplest problems. I can imagine that most of you would get a committee, have long meetings where you talk about 'think out of the box', and 'at the end of the day' nonsense. This is an interesting logic question, but I would not want to buy fruit from a company who knew they had a problem and then sampled one out of three boxes to resolve the issue. There are other correct answers posted. I'll just make a comment: "The boxes have been incorrectly labeled such that no label identifies the actual contents of the box it labels." Nothing in the above statement says the labels are limited to oranges/pears, only that they do not identify the contents. They could say 'nuts', 'bolts', etc. Technically, all answers should be prefaced with: assume that the labels say 'oranges', 'pears', and 'orange/pears'. Ok, the problem does not make sense and is unsolvable if the labels say 'x', 'y', 'z', but someone with (likely with a math proof back ground) may appreciate attention to detail. Q: Why do posters denigrate the interview questions? The questions, however stupid they may be, are a opportunity to show you can build an answer. Even if you pursue an invalid train of thought in the interview, it's a thought. It's what they want to see and what will help you get a job offer. Note: I also would not assume that the questions asked are a reflection on the company, department, or team as a whole. It may just be the interviewer that has chosen poorly. So to say "I don't want to work for company X because they asked me a stupid interview question" is pretty closed minded. To even think I don't want to work with that interviewer just based on questions asked seems extreme. rightly pointed out by Sagmi ... this question was put forward to me at Huawei Technologies and that was the answer I gave So the question was asked at an interview for Apple: Label ALL the boxes apple and charge a ridiculous price for them! Just label all of them "Fruit." Put another way, it is not possible to tell since we don't know how the boxes are mis-labled. What if the Apple box was labeled Oranges and both the other boxes were labeled Apples and no box was labled Apples and Oranges? You might have assumed there are three different labels when their might have only been two different labels. Always pict a piece of fruit from the box labelled Apple&Orange. As we know that this label is wrong, there are two possibilities: If it is apple, then wo know that this box should be labelled Apple, so we switch Apple label with the label Apple&Orange. Then Apple label is correct. We also know that the Orange label is incorrect, so we then switch Orange label and Apple&Orange label. if it is orange, then we know that this box should be labelled Orange, so we switch Orange label with label Apple&Orange. Then Orange label is correct. The same as above, we know that the Apple label is incorrect, so we switch Apple label and Apple&Orange label. If all boxes are labeled incorrectly and u pick a orange out of a box that's labeled apple/oranges change the name to oranges then change the box labeled oranges to apples and the the box labeled apples to apple and oranges... If you pick a apple out of a box labeled apples and oranges change the name to apples and then change the box labeled apples to oranges and the last to apples and oranges... If u pick a apple out of a box labeled oranges change it to apples and oranges then the box labeled oranges to apples and the box labeled apples to oranges...if you pic a orange out of a box labeled apples change it to apples and oranges and the box labeled oranges to apples and the last to apples and oranges... See the pattern? I think there is a big box and it contain two small boxes and all the labels are incorrect so big one contain two boxes that makes it carrys both orange and apples and in that thwo boxes having orange and apple respectively so if we open any box we can label it correctly Show More Responses To see the java source code of puzzle, visit: https://github.com/SanjayMadnani/com.opteamix.microthon code is taking the input by console only. You can fork or clone the repository and proceed further. You can also rise bug if you find any. Run BasketPuzzleGameTest.java class as a Junit test case to start game. if it known already that boxes labeled incorrectly, I would give it back to those who did label them and ask to fix this confusion. it is impossible to tell by opening only one box, so you have to open one more box. As mentioned already, if you start with the A+O bucket, you can solve the puzzle by pulling only one fruit, Bucket: A+O Found: A Bucket A+O > A | A+O, but since A+O label is incorrect, then it must be A Bucket O > since A is taken, the new label must be O | A+O, but since O is incorrect, it must be A+O Bucket A > since A and A+O are taken, it must be O Bucket: A+O Found: O Bucket A+O > O | A+O, but since A+O label is incorrect, then it must be O Bucket A > since O is taken, the new label must be A | A+O, but since A is incorrect it must be A+O Bucket O > since O and A+O are taken, it must be A If you are lucky, you might solve it with just one fruit even if you start with other buckets, Bucket: A Found: A Bucket: A > A | A+O, but since the A label is incorrect, it must be A+O Bucket: O > A | O, but since the O label is incorrect, it must be A Bucket: A+O > since A+O and A are taken, it must be O Bucket: O Found: O Bucket: O > O | A+O, but since the O label is incorrect, it must be A+O Bucket: A > A | O, but since the A label is incorrect, it must be O Bucket: A+O > since A+O and O are taken, it must be A If you start with the A bucket and pull an O or if you start with the O bucket and pull and A, then you are SOL and you need to pull out more fruits to figure it out. 1. Open one box and check its contents. 2. Remove the current label and apply the correct one (by removing it from one of the other boxes) 3. Since all boxes have been labeled incorrectly, switch labels between the other 2 boxes. And Voila you have all the boxes labelled correctly :) In requirement already specify that all three box labels are not correct. A+O A O Step1: First Pick an item A+O Box. If you get an Apple then it is a Apple Box. swap the label . A A+O O AS we already know in the box that label with Orange, does not contain Orange because of wrong label. So It must contain A+O. Just Swap the label A O A+O OK, all 3 boxes are incorrectly labeled. Open the one that says apples and oranges. Whatever is in there is what it is (since it cannot be apples AND oranges). Now, if there was an orange in there, apples must be in the orange box (since they cannot be in the apples box), and apples and oranges in the apples box (due to process of elimination). Get it? I guess questions like these will appear easy if you put them on paper, it is the possible combinations that become relevant, one way to approach is.. One of the key factor is all boxes are labelled incorrectly, this gives rise to only (2) combinations right To label for 1st box incorrectly you will have (2) options, once you label it then you have only choice to label the other two boxes incorrectly so 2 x 1 = 2 combinations possible i.e. Incorrect lablling options { Boxes_with_Oranges, Boxes_with_Apples, Boxes_with_Apples&Oranges } = { A, AO, O} or {AO, O, A} 2. To know for sure the contents of the boxes, you need to pick the box with either Apples or Oranges and avoid box with Apples and Oranges. So from the (2) combinations you could pick a fruit from Box_labeled AO (this will contain either Oranges or Apples) So, if you get a Orange, it means that combination is{AO, O, A} , so that means Box_with_Label_O has Apples, Box_with_Label_A has Apples and Oranges Box_with_label_AO has Oranges or else if you get a Apple that combination is {A, AO, O}. Box_with_Label_AO has Apples, Box_with_Label_O has Apples and Oranges Box_with_label_A has Oranges Then you can correctly label all the 3 boxes. First answer in this post is correct, as its said all boxes doesnt reflect correct items in it, If an apple is picked from a box , then it can be from either A/O box or A box, if the box is names A/O the, the label of the box has to be changed to A, then other two box labels to be accordingly. It is interesting that in 6 years people keep overthinking this. The answer is in the question and the criteria are that the boxes are immediately labeled and they are labeled correctly. ANSWER: FRUIT FYI you don't even need to open one box. Show More Responses Your choice going to be (( 2 apple 1 orange)) or (( 2orange 1apple )) . It can be recognize only one box (x) . U have to chose again until u get another formula then u will named easly . Step 1: Open a box labeled ‘Apples and Oranges’. We know that this box does not contain ‘Mixture’ for sure. If this fruit is an apple, then label this box as ‘Apple’. Step 2: (Very important) If we look at the box labeled as ‘Oranges’, we know that since the label is incorrect, this box either has only apples in it or has Mixture. Since we already know which box contains only apples, we know that the box labeled as ‘Oranges’ contains ‘Mixture’. So label it as ‘Mixture’. Step 3: (Very easy) The 3rd box will be labeled as ‘Oranges’. When you put your hands on the box to pick the fruits by touching every fruits you can feel whether all are apple or oranges or both and just pick one to see.So it is not necessary to pick one fruit and see whether it is orange or apple also it is not said in question that you can touch and feel all the fruits inside the boxes without taking it out .and then you can fix the label correctly on the boxes. Absurd, no logic km I will took a pen and stab the apple. and then ? apple-pen. |

### Software QA Engineering at CareFusion was asked...

You have nine coins, eight of which weigh one ounce, and one weighs 1.1 ounces. You have a "judge's scale" with which to weigh them. What are the fewest steps necessary to determine which coin is the 1.1 ounce coin? Illustrate on the white board how you'd solve this problem. 4 AnswersI believe the question is phrased wrong: "steps" should be "weighings". In this case, there are 2 answers: 1 or 3. Split the coins into 3 piles (4, 4, and 1). Put the sets of 4 onto the scale. If the scale is even, then the coin left out is the 1.1 oz coin. If not, remove the lighter side. Take the heavier side and split it into 2 piles (2 and 2) and put them on the scale. Remove the lighter side. Take the 2 remaining coins and put 1 on each side of the scale. The heavier one is the 1.1 oz coin. 2 weighings 1 - unreliable instead 3 piles of 3 coins each 1. measure 3 Vs 3 if weight same go to the remaining pile and do 1 vs 1. If weight same then the remaining coin is the heaviest. 2. If one pan is heavier then do one vs one for this one and get the heaviest this way while these answers are "intellectually" accurate, we're dealing with nine coins. The time it would take to divide, stack, re-divide and so on would probably be the same or more than just flipping each coin off and on the scale quickly. lame Show More Responses Assuming splitting the coins and weighing is one step... I think this can be achieved in 2 steps as well..having said that it can be done in 1 step (Lucky case).. Dividing into 3 different blocks A B C with three coins each.. weighing A and B if they are of equal weight..then the coin has to be in 3rd or the highest weight of A and B is split into 1 coin each and any 2 coins are weighed again... If both show same weight then the coin left over has more weight..else its either of the 1st 2 coins that has more wight... |

### QA Software Engineer at eBay was asked...

You have five bottles with pills. One bottle has 9 gram pills, the others have 10 gram pills. You have a scale that can only be used once. How can you find out which bottle contains the 9 gram pills? 5 AnswersNumber the bottles 1-5. Collect a number of pills from each bottle corresponding to their bottle number. So, 1 pill from bottle 1, 2 from bottle 2, etc. If they all had 10 gram pills they should weigh 150 grams. The difference will be the number of the bottle the 9 gram pill came from. Example, bottle 3 has the 9 gram pills. Total weight read will be 147 grams. The difference of 3 is the bottle it came from. Did u get the job? What was team where you interviewed for ? Read the label on the bottle. Show More Responses Place all five bottles on the scale. It should say 49 grams on the scale. If you take out one bottle each time. Subtract the scale from before and after the bottle that has been taken off the scale. If it's 9. That's the bottle you're looking at. What top poster said except you can label the bottles from 0 to 4 and save yourself a little work |

### Software QA Engineer at Apple was asked...

how to test a toaster? 4 AnswersPlug the toaster into a PowerPoint. Turn the power point on. Place required number of slices of untoasted bread in the toaster - dependant on slots available. Press the Press the lever down to lower the toast into the toaster. Contined...prior to lowering the bread into the toaster select the lowest heat setting. Once the bread is lowered set a timer to measure length of time before toast cycle completes and toasted bread pops up. Retest on all other heat settings and time each of these. I would find a tester and I'd tell him/her to test the toaster by plugging it in. If the toaster doesn't toast the tester, it works; if it toasts the tester, it's broken. Show More Responses Did not understand this part of your answer, could you please eloborate. "If the toaster doesn't toast the tester, it works; if it toasts the tester, it's broken." |

### Software QA Engineer at NetApp was asked...

Write a program printing '"hello World" without semi colon in c. 2 AnswersMala Punyani [12/3/2010 12:10:32 PM] Mala Punyani: #include main() { if(printf("Hello World \n")) { } } I wonder why such a question is needed? They don't like semi colons in their code is it? ;) |

### Software QA Engineer at eBay was asked...

how to find the closest 2 number in an array of unique positive number 5 Answersasked during phone interview One solution is to sort the array, then iterate through all neighboring pairs to find the pair with smallest difference. This is O(NlogN) solution. If the integers are bounded, you may be able to sort in O(N) time for an O(N) solution. public static int[] find2Closest(int[] myArray) { assert(myArray.length >= 2): "myArray needs to be larger than 2"; Arrays.sort(myArray); //quickSort int indexMin1 = 0; int indexMin2 = 1; int min = myArray[indexMin1] - myArray[indexMin2]; for(int k = 0; k < myArray.length-1; k++) { int difference = Math.abs(myArray[k] - myArray[k+1]); if(difference < min) { min = difference; indexMin1 = k; indexMin2 = k+1; } } int[] values = new int[2]; values[0] = myArray[indexMin1]; values[1] = myArray[indexMin2]; return values; } Show More Responses public class ClosestTwoNumber { public int[] findClosest2Number(int[] arr){ if(arr == null || arr.length diff) { min = diff; num1 = arr[i - 1]; num2 = arr[i]; } } if (num1 == -1 || num2 == -1) { throw new IllegalArgumentException(); } int[] result = new int[2]; result[0] = num1; result[1] = num2; return result; } public class ClosestTwoNumber { public int[] findClosest2Number(int[] arr){ if(arr == null || arr.length diff) { min = diff; num1 = arr[i - 1]; num2 = arr[i]; } } if (num1 == -1 || num2 == -1) { throw new IllegalArgumentException(); } int[] result = new int[2]; result[0] = num1; result[1] = num2; return result; } |

### Software QA Engineer at Golden Frog was asked...

Even though the interview was with HR, there was 1 technical question; specifically “what happens when you put a web address into your browser, and press Enter”, and you had to describe in detail what happens from there. 2 AnswersThey were looking to see if you understand the basic principles of HTML. When you navigate to any web page, your machine (the client) makes a request called a GET to the server, it asks for all of the resources that are required to show the web page to you, the server receives this request and, depending on a variety of circumstances returns either a successful response to your machine which is then processed by the browser that you are using, turning it into what you see, or the request fails for some reason and returns an error code, the most common of which is 404: Resource not found. Not only HTML, but DNS as well. When you put www.google.com into your browser's address bar your browser queries your DNS server (typically run by your ISP but you can set it yourself too) to see if there is an IP address linked to that web address. If the DNS query resolves then your browser attempts to contact the server and load the content. |

http protocol status codes. 1 Answerchk the website for status codes |

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