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By far the easiest way is to test for material properties. -density -hardness -modulus of elasticity I would choose hardness. Strike each item with an equal force, which one deforms more? Thats aluminum. You could probably pull this test off with a hammer. The simplest solutions is always the best. Less
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Simple methods would be density (feeling the mass of the object), surface finish (color, texture). If coated that may give you the answer i.ie anodized would indicate aluminium. For more information I would go for EDX( Energy-dispersive X-ray spectroscopy) and possible a cross section to look at the grain structure. Less
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Density, thermal conductivity, electrical conductivity, strength, harness
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5 different variables that can affect the springs force. 1.) Wire length 2.) Coil pitch 3.) Wire cross-sectional shape 4.) Material of the coil 5.) Coil diameter Less
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1. WD 2. OD 3. Active coils 4. Material 5. Free Height
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Material, wire diameter, wire cross sectional shape, coil diameter, coil length
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Reduce the length, increase the thickness, change the material to one with a stronger young's modulus (just have to be careful about the tradeoff between material density and stiffness). Less
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Taper it.
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What is the weight of the load? What is the weight of the beam? Does the beam even need to be changed? Certainly you can shorten the beam , you could also turn the beam 90 degrees so the taller end is pointing upwards. There are questions that should be asked before any answers are given. Less
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I listed the design/office related programs I am proficient in.
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Bigger spaces, such as hospitality, retail etc.
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@Rajiv : Your solution is completely wrong. It will fail for input of "aaa" Reason: on first check, you insert "a". On next check you remove it. On next check you again insert it and return that as your answer, even though it was repeated thrice. Less
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program to find first non repeating character in a string c# - three ways
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My python implementation: def firstNonRepeatingCharacter(inputString): hashmap = {} for x in inputString: if (x in hashmap): hashmap[x] = hashmap[x] + 1 else: hashmap[x] = 1 for x in inputString: if (hashmap[x] > 1): continue else: return x return "No nonrepeating character found" Less
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Hey, you should feel glad that you weren't accepted by them. This company is very cheap and doesn't treat its employees well. Less
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I guess...but it is not the right way to interview candidates don't you think?
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That's really sad. They should rather go with Skype or any other means to interview. Now,. I have got an on-site call for Digital circuit design and I am giving it a serious thought 🤔 Less