An intelligence analyst evaluates data and information to identify security risks and mitigate them for various organizations. Some intelligence analysts work for government agencies, but the field is broad and spans across various industries. When interviewing for a position as an intelligence analyst, you may face questions about the tools you use to identify risks.
Here are three top intelligence analyst interview questions and how to answer them.
How to answer: An interviewer uses this question to understand your methods and processes for managing important tasks. Use the STAR method to describe a specific situation that demonstrates how you analyze data to identify potential security risks for an organization and take action.
How to answer: Data analysis is part of the role of an intelligence analyst, but this individual also needs to be able to track the data they use and disseminate it across the intelligence team. When answering this question, talk about the software or tools you have experience with that allow for accurate data analysis and management.
How to answer: This question allows you to share your perspective on the role of an intelligence analyst and their responsibilities to an organization. Your perspective might outline the importance of mitigating security risks or describe the responsibility of protecting a group of people.
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This is incorrect Old revenue = 50000*250*.005=250*250 New revenue with conversion rate r% = 50000*r*250*.9 = old revenue = 250*250 r = .55% Less
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July 9 is wrong because the profit margin changes(As sale price changes, but the cost doesn't change) Less
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The new conversion rate is 0.944, Profit from case 2 = $16,875 and the third part, if this scenario actually occurred I would give a 10% discount (with the new conversion rate .944%) because the overall profit margin would remain same i.e. $16,875 Less
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SELECT for which columns to include in the result, (tables must be present in the FROM clause), can also include aggregates like COUNT(), SUM(), AVG() FROM for which tables to select rows/attributes from WHERE which is used to filter rows based on a given criteria with comparisons (=, !=, , and keywords LIKE and BETWEEN), INNER JOIN and LEFT/RIGHT OUTER JOIN to combine data across multiple tables ORDER BY DESC/ASC to specify ordering of a specific column name GROUP BY to group data based on the tables passed HAVING to filter rows based on an aggregate used in the SELECT statement that cannot be used with the WHERE clause Less
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I described a simple statement: Select (Name all columns from tables or use * for all) From (table name(s)) Where (any conditions, join statements ect) Group By / Order By to sort or aggregate the data Less
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I explained how a clustered index was in sequential physical order on disk and a non clustered index used pointers or a hash table for index lookup. I started to explain the advantages/disadvantages of each index type but the two guys interviewing me just seemed so confused and lost. I think I would have been better of simply saying "it makes lookup faster". Less
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I explained how a clustered index was in sequential physical order on disk and a non clustered index used pointers or a hash table for index lookup. I started to explain the advantages/disadvantages of each index type and how I would use them. Less
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Inner Join returns values where the key between the two tables are the same, and values are present in both tables. Outer Join returns the Values from both tables, based on the key, even if there is not any data the joining table. If not value is available, then NULL is returned for that specific Row Data based on the Key Less
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Specified in the WHERE clause, joins simply combine data from multiple tables in the result. INNER JOIN, the most common, returns the rows for which the given ON condition is satisfied for both tables. LEFT/RIGHT OUTER JOIN statements return all the rows from the specified table regardless if there is a match in the unspecified table, with the matching rows specified in the ON condition in the unspecified table. Less
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The interviewer was interested in breath of experience rather than specific technical skill. Unix work with scheduling and XML skills are necessary, but not heavy (the same procedures are done over and over again). Emphasis was on selling yourself through experience. Less
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An average in which each quantity to be averaged is assigned a weight. These weightings determine the relative importance of each quantity on the average. Weightings are the equivalent of having that many like items with the same value involved in the average. Less
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It's a great question but analogous to asking, "What's the best house or the best car?". The answer depends on several factors. I'd start with requirements and budget and discuss what is possible within those parameters. If you watch "Property Virgins" on HGTV, the educational process is similar, as are the "buyers" perceptions. Less
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Customer problem: select customerId from orders group by customerId having count(distinct date(orderDate)) > 1; -- Assuming the orderDate has time associated with it. Flights problem: select arrival, departure from flights union select departure, arrival from flights; Less
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select distinct(b.id) from ( select a.id, a.d, a.#items, row_number() over (partition by id order by d) as rn from ( select id, d, sum(q) as #items from cust group by id, d having sum(q) >=2 ) a)b where b.rn>2 Less
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CREATE TABLE test_flights ( origin VARCHAR(255), destination VARCHAR(255) ); INSERT INTO test_flights (origin, destination) VALUES ('Boston', 'Los Angeles'), ('Los Angeles', 'Boston'), ('New York', 'Pittsburgh'), ('Pittsburgh', 'New York') SELECT * FROM test_flights WHERE origin < destination Less
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probability of the product coming from location A is 0.8 and from location, B is 0.6. What is the probability the customers will receive the product from location A or location B P(A)=0.8 P(B)=0.6 Assuming the events are independent: P(A OR B) = 1 - P(not A AND not B) = 1-(0.2*0.4) = 1-0.08 = 0.92 The other ways: P(A or B) = P(A) + P(B) - P(A AND B) = 0.8 + 0.6 - (0.8*0.6) = 1.4 - 0.48 = 0.92 OR P(A or B) = P(A) + P(B )*P(not A) = 0.8 + (0.6*0.2) = 0.8 + 0.12 = 0.92 OR P(A OR B) = P(B) + P(A)*P(not B) = 0.6 + (0.8*0.4) = 0.6 + 0.32= 0.92. Less
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helpful
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P(A)=0.8 P(A')=1-0.8= 0.2 P(B)= 0.6 P(B')= 0.40 P(A or B)= P(A)P(B')+P(B)P(A') It means from location A and not from B, OR, from location B and not from A Ans: 0.8*0.4+0.6*0.2 => 0.44 Less
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I got 5.75% for the first question and 5.86% for the second part of the question. I assumed we are sending out the catalogs to a total of 100 people and that the cost of the catalog is not calculated as part of the profit margin which means we can expect 5 people to buy from the catalogs (5*315*.3)-(.5*100) = 422.5 dollars in profit from the first catalog. Now 422.5 = 100x * .3 * 300 - (.95*100) = .0575. For the second part I assumed we are comparing the 20/80 split with the option of only sending the second catalog. So we make $338 from the second catalog (80% * 422.5) so now we just need to solve for x: 422.5 - 338 = 20x * .3 *300 - (20 * 1.05) leaving us with x = .0586 Less
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1) Conversion % for Catalog 2(.95 cents) = 5.25% ((Average Sale price($315) * Conversion rate))/New Average selling price ((315*5))/300 = 1575/300 = 5.25 2) Conversion % for Catalog 3(1.05 cents) = 21% Since Average selling price and profit margin are the same for both - IGNORE them. The ratio of the reach is 4:1 (80%:20%)... So, just by eyeballing, you know that the third catalog must perform 4 times better than the second one - which is, 5.25*4 = 21% Nothing is missing from the question, there's a lot of garb that you need to ignore to get the answer. Less
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part 1 : 5.4% part 2: 5.5% -don't use PM -just do a regular Revenue - Cost -no point multiplying Revenue with PM-> this would just yield profit instead of Revenue (as done in some questions above) Less