Behavioral Interview Questions

There is a difference between being "friends" and being "friendly". I strive to be friendly to all people at all times and I believe this attitude helps build rapport between students and their teachers; however, I do not believe it is appropriate to establish friendships between students and teachers.

this answer sounds terrific. just wondering if it would add any value by stretching the reason for this clear distinction in terms of why this distinction is so important. any comments from HR specialists???

This is a TRAP! The answer is NO. Exemple : "I have a very good relationship with my student and it is based on mutual respect. I represent the authority in the classroom. This does not mean that I can't listen to them, or communicate, give them advices and be accessible. But establishing friendship with my student would cross the line, and I would not do that".

Need to be able to show you can highlight some of the positive attributes of the tape dispenser, and while you're at it, you might as well pick something else up from the desk and try to package it together with the tape dispenser.

Introduce yourself the the "customer" - Hi, I'm bla bla bla, im going to sell you shiii... Ask questions..."what kind of dispenser do you have now?" "what do you find important in a dispenser?"... Recommend the item you are selling, based on what you now know of the "customer" - "I know you need double sided tape that is reliably sticky, at an affordable price, you should check out this brand." Ask them if they want to buy it, by saying- "do you want me to ring this up?" or "do you want this black one, or would you like the white one from the back room?"

I would of said , sorry sir we don’t sell tape dispensar.

I request the existing client to step aside momentarily which I then assess all my available resources to assist this client. Should it then become heated I attain a manager to resolve the situation.

I politely tell the client who interrupted to please standby and that I will be able to answer their questions/handle their issues shortly. If they need immediate attention I will call a member of the team to assist.

I apologize and ask him or her to please step in line and I’ll be right with them. If they interrupt I say understand completely and look for a manager. If there isn’t one available, I’d ask for the source of their urgency. If it’s just them being difficult without an interest in telling me their issue I’d tell them I’ll be with them shortly, I just have to help another customer. Really it helps to keep things short and simple, moving along as quickly as possible with other tasks at hand.

ANS: Vout should be constantly -10V until t=0, and will hit V=0 V linearly from V=-10 V after t=0.

Hi, Can you explain why it linearly increases? Are you assuming that Collector is tied to -10V? The pnp transistor is completely cutoff for the given biasing. The only way the capacitor is going to charge is through leakage currents. It is very slow and takes a lot of time. Please advise me if my analysis is correct.

I just made it back from Lutron's HQ and I was asked for the same question. My first approach will be identifying a PNP BJT, and elaborating all 4 BJT operating regions. Before t = 0, since q = 0, by using Q = CV, we can tell that the voltage across the capacitor is 0. Hence, Vo = -10V before t = 0. Recall the capacitor's current equation: I = C*(dv/dt), we can solve for the slope of changing voltage -> dv/dt = I/C. Here, I is simply the BJT's collector current, which can be found by looking at the BJT's emitter current. Given that the (beta) parameter is infinite, we see the base current to be 0. Now, at this point, we need to look for I_E. Since the R is given to be 9.3k, and VEE = 10V, it is natural to assume V_EB = 0.7V, and thus the voltage across R = 9.3V. Therefore, I_E = 9.3/9300 = 1mA. Voila, we now values for all currents: I_E = I_C = 1mA, and I_B = 0A. Plug the I_C value into the equation: I_C/C = dv/dt (C = 1uF). We know that the slope of the voltage change is 1000V/second, or 1 Volt per millisecond. Now, we know the capacitor voltage raises at 1V/ms from -10V, but we also need to know where is the upper limit. Looking back to the BJT basics about operating regions and BJT's 2-diode model, it is not hard to identify that this PNP BJT must operate in "Saturation" region (NOT IN "ACTIVE" REGION!). The boundary of that region is V_BC <= 0.7V (I hope everybody is able to solve for this). Hence, 0.7V will be the upper limit for capacitor voltage. At this point, you will have a flat line at Vo = -10V before t = 0. and raises at 1V/ms for 10.7ms and hit Vo = 0.7V. From t = 10.7ms and on, the Vo stays at 0.7V.

First, try and reproduce the problem and if the problem could be reproduced acknowledge there was an issue, give thanks for bringing this to the company's attention, and apologize for the customer's encounter with the issue. Offer possible solutions or workarounds while the team worked to correct the issue.

I was somewhat stumped. Having such little information, I was left to say that I would simply prioritize based on the patients' acuity as well as do my best to ensure that anything I was doing wouldn't throw off the schedule of any other department in the hospital. I'm not sure how it went over. We'll see. It's only been a day and I haven't been contacted about an offer or anything to the contrary. But I left with generally positive feelings about the interview.

Provided a situation early in my career as a Project Manger where mistakes are expected. I detailed how I learned from the experience and what I do now to mitigate that from happening again.